(1/2x)^2-3x=7x+8-10x

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Solution for (1/2x)^2-3x=7x+8-10x equation: 


x in (-oo:+oo)

((1/2)*x)^2-(3*x) = 7*x-(10*x)+8 // - 7*x-(10*x)+8

((1/2)*x)^2-(3*x)-(7*x)+10*x-8 = 0

((1/2)*x)^2-3*x-7*x+10*x-8 = 0

1/4*x^2 = 8 // : 1/4

x^2 = 32

x^2 = 32 // ^ 1/2

abs(x) = 4*2^(1/2)

x = 4*2^(1/2) or x = -(4*2^(1/2))

x in { 4*2^(1/2), -(4*2^(1/2)) }

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